question will be attached Given the matrices A and B below, find A + B and 3A
to find A + B you just add by position so [3 -3;10 9/5;10 -1]
and 3A is just multiplying each entry by 3 so [6 -9; 0 15; 21 -6]
understand?
so I will just have to add the numbers up across? [2+ (-3)]?
no no 2+1
the top left of A with the top left of B
then put that in the top left of the new matrix
\[\left[\begin{matrix}a & b \\ c & d\end{matrix}\right]+\left[\begin{matrix}e & f \\ g & h\end{matrix}\right]=\left[\begin{matrix}a+e & b+f \\ c+g & d+h\end{matrix}\right]\]
\[3\left[\begin{matrix}a & b \\ c & d\end{matrix}\right]=\left[\begin{matrix}3a & 3b \\ 3c & 3d\end{matrix}\right]\]
ohh ok I get it now thank you :) then for 3A I just multiply each by 3?
yes
multiplying matrices is a different story and its not as easy, but a constant times a matrix is easy
we call the later scaling the matrix by a factor of 3
ok got it, thank you very much :)
np
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