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Mathematics 18 Online
OpenStudy (anonymous):

question will be attached Given the matrices A and B below, find A + B and 3A

OpenStudy (anonymous):

OpenStudy (zzr0ck3r):

to find A + B you just add by position so [3 -3;10 9/5;10 -1]

OpenStudy (zzr0ck3r):

and 3A is just multiplying each entry by 3 so [6 -9; 0 15; 21 -6]

OpenStudy (zzr0ck3r):

understand?

OpenStudy (anonymous):

so I will just have to add the numbers up across? [2+ (-3)]?

OpenStudy (zzr0ck3r):

no no 2+1

OpenStudy (zzr0ck3r):

the top left of A with the top left of B

OpenStudy (zzr0ck3r):

then put that in the top left of the new matrix

OpenStudy (zzr0ck3r):

\[\left[\begin{matrix}a & b \\ c & d\end{matrix}\right]+\left[\begin{matrix}e & f \\ g & h\end{matrix}\right]=\left[\begin{matrix}a+e & b+f \\ c+g & d+h\end{matrix}\right]\]

OpenStudy (zzr0ck3r):

\[3\left[\begin{matrix}a & b \\ c & d\end{matrix}\right]=\left[\begin{matrix}3a & 3b \\ 3c & 3d\end{matrix}\right]\]

OpenStudy (anonymous):

ohh ok I get it now thank you :) then for 3A I just multiply each by 3?

OpenStudy (zzr0ck3r):

yes

OpenStudy (zzr0ck3r):

multiplying matrices is a different story and its not as easy, but a constant times a matrix is easy

OpenStudy (zzr0ck3r):

we call the later scaling the matrix by a factor of 3

OpenStudy (anonymous):

ok got it, thank you very much :)

OpenStudy (zzr0ck3r):

np

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