Determine whether the graph of y = x2 − 6x + 3 has a maximum or minimum point, then find the maximum or minimum value.
well this one you would need to use a graphing calculator to determine them but it easy enough to say it has none, anything that is a variation of y=x^2 is a parabola which is only a u-shape so if anything it has 1 minimum but if i remember they regard parabolas as none.
The multiple choice answers that they are giving me is Minimum; (-6, 3) Maximum; (-6, 3) Minimum; (3, -6) Maximum; (3, -6)
hmmm ok then there is a minimum
So how would i do this
make a simple graph of it, using a x/y chart and 3 simple points or if you can figureo ut it's vertex because that would be the minimum
find the vertex
Ohhhhh ok
first coordinate of the vertex of \(y=ax^2+bx+c\) is \(-\frac{b}{2a}\)
Ok
in your case it is \(-\frac{-6}{2\times 1}=3\)
ok
the second coordinate of the vertex is what you get for \(y\) when you replace \(x\) by \(3\)
OHhhh ok
Then i would have to plug in x
Which is 3
correct
which i guess you do not have to do in this case, because the only choice is \((3,-6)\)
YEHHHH I GOT THAT ANSWER 8'D /dance
pick C because it is always C
It would be a minimum right awesome
yes, a minimum
If i have more questions i will ask you guyz.
k
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