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Prove that cot^2(x)/(cscx+1)=(1-sinx)/sinx
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try putting csc x = 1/sin x and cot^2 x = ( 1 - sin^2 x)/ sin^2 x
- and see what it simplifies to
\[(cosec ^{2}(x)-1)\div (cosec(x) +1)=cosecX-1= (1\div sinX)-1=(1-sinx)\div(sinX)\]
Cwrw238, im sort of still confused:/ after you plug those in would you flip the 1/sinx to the top making it
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