What is the range of the function y = -x2 + 1? i really need help please
the very smallest \(x^2\) can be is zero because if you square a non zero number it is always positive that means the very LARGEST \(-x^2\) can be is zero
so now what is the very largest \(-x^2+1\) can be?
if it is not obvious, let me know
o.o......uhh, 1? I really have no idea. im 100% dislexic in algebra and my only two teachers been the worst in the entire school.
yeah it is one, because... well because if the largest \(-x^2\) can be is \(0\) then the largest \(-x^2+1\) can be is \(0+1=1\)
okay..
now that should answer the question, because the range is all possible \(y\) values
\(y\) cannot be any larger than 1, so the range can be written either as \(y\leq 1\) or \[(-\infty,1]\] depending on how you are supposed to write your answer
Im sorry for wating your time. But thank you.
btw i knew right away you had a lousy math teacher because of the way the question was asked \[y=-x^2+1\] is not a FUNCTION it in and EQUATION
oh...
not a waste at all, glad to help and i hope it was more or less clear
you can make it a function by writing \[\{(x,y):y=-x^2+1\}\] or more commonly by saying "let \(f(x)=-x^2+1\) "
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