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Use the Binomial Theorem to expand the expression (2y-3x)^5
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first find the fifth level of pascal's triangle for the coefficients
do you know it?
no
lol google!
there is tons even "images" will be good the fifth level is the one that starts 1, 5
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did you find it yet?
binomial theorem of (a + b)^n = \[\sum_{k=0}^{n} \left(\begin{matrix}n \\ k\end{matrix}\right) a^{n-k}b^{k}\]
the fifth level is the one with the number 1 , 5, 10, 10, 5, 1
ok i got it, thanks again
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those are you coefficients then the powers have to add up to 5, so you can start with \[ (2y-3x)^5\] \[=(2y)^5-5(2y)^4(3x)+10(2y)^3(3x)^2-10(2y)^2(3x)^3+5(2y)(3x)^4-(3y)^5\]
then you have a bunch of multiplication to do if it was me, i would cheat
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