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Mathematics 20 Online
OpenStudy (anonymous):

Solve 2x - 1 < 7 and 5x + 3 < 3. {x | x < 0} {x | x < 4} {x | 0 < x < 4}

OpenStudy (austinl):

solve for x in each equation. Can you do that for me?

OpenStudy (anonymous):

i think i can hold on let me try

OpenStudy (austinl):

inequality, excuse me.

OpenStudy (anonymous):

omg i just forgot what an inequalty is

OpenStudy (austinl):

Those things up above lol. 2x - 1 < 7 and 5x + 3 < 3

OpenStudy (anonymous):

oh my bad

OpenStudy (anonymous):

ill give medal for best answer

OpenStudy (austinl):

I kinda broke the rules before. You need to put in some effort. Do you know where to begin with the first inequality? 2x - 1 < 7

OpenStudy (anonymous):

yes add 1 to both sides and it leaves me with 2x<8

OpenStudy (anonymous):

then divide by 2 on both sides and i get x<4

OpenStudy (anonymous):

right?

OpenStudy (austinl):

Correct. Now can you do it for the other inequality. 5x + 3 < 3

OpenStudy (anonymous):

divide by 5 on both sides and i get x + 3 < 1\[\frac{ 2 }{ 5}\]

OpenStudy (anonymous):

-3 on both sides and i get x< -2 \[\frac{ 2 }{ 5 }\]

OpenStudy (austinl):

Not what I would do... I would subtract the three over to get 5x<0... x<0

OpenStudy (anonymous):

ohhh ok thanks so it would be {x | 0 < x < 4}

OpenStudy (austinl):

I believe so, but I have been wrong before. I am only human.

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