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Mathematics 19 Online
OpenStudy (highschoolmom2010):

solve for x and y

OpenStudy (highschoolmom2010):

OpenStudy (highschoolmom2010):

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OpenStudy (rsadhvika):

|dw:1374072589612:dw|

OpenStudy (highschoolmom2010):

thats what i wasnt sure of

OpenStudy (highschoolmom2010):

\[{\sqrt{63}}=\sqrt{x^2}\]

OpenStudy (rsadhvika):

mark one angle as \(\alpha\) , then you need to follow orientation to steup a proportion once you get it, you will be confident

OpenStudy (rsadhvika):

keep going, simplyfy the radical

OpenStudy (highschoolmom2010):

\[\sqrt{63}=\sqrt{9*7}\] \[\sqrt{9}\sqrt{7}\] \[3\sqrt{7}\]

OpenStudy (rsadhvika):

correct, y you can find using pythagorean

OpenStudy (highschoolmom2010):

ok let me try that

OpenStudy (rsadhvika):

still, you're clueless in setting up the first proportion, i can see that... we can work on that if you want, after you finish solving y

OpenStudy (highschoolmom2010):

y^2=9^2+3sqrt7^2 like that....?

OpenStudy (rsadhvika):

yes y^2=9^2+(3sqrt7)^2

OpenStudy (highschoolmom2010):

or am i supposed to use the whole triangle

OpenStudy (rsadhvika):

for using whole triangle, you dont know the other leg. So you cant use the whole triangle

OpenStudy (highschoolmom2010):

ok so i was right the first time y^2=9^2+(3sqrt7)^2 y^2=81+63 y^2=144 \[\sqrt{y^2}=\sqrt{144}\] y=12

OpenStudy (rsadhvika):

yes !

OpenStudy (highschoolmom2010):

i think i got it now :DDDD

OpenStudy (rsadhvika):

good :) more you do more confident you wil feel gotta run, cya

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