Mathematics
19 Online
OpenStudy (highschoolmom2010):
solve for x and y
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OpenStudy (highschoolmom2010):
OpenStudy (highschoolmom2010):
|dw:1374072509216:dw|
OpenStudy (rsadhvika):
|dw:1374072589612:dw|
OpenStudy (highschoolmom2010):
thats what i wasnt sure of
OpenStudy (highschoolmom2010):
\[{\sqrt{63}}=\sqrt{x^2}\]
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OpenStudy (rsadhvika):
mark one angle as \(\alpha\) , then you need to follow orientation to steup a proportion
once you get it, you will be confident
OpenStudy (rsadhvika):
keep going, simplyfy the radical
OpenStudy (highschoolmom2010):
\[\sqrt{63}=\sqrt{9*7}\]
\[\sqrt{9}\sqrt{7}\]
\[3\sqrt{7}\]
OpenStudy (rsadhvika):
correct, y you can find using pythagorean
OpenStudy (highschoolmom2010):
ok let me try that
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OpenStudy (rsadhvika):
still, you're clueless in setting up the first proportion, i can see that... we can work on that if you want, after you finish solving y
OpenStudy (highschoolmom2010):
y^2=9^2+3sqrt7^2
like that....?
OpenStudy (rsadhvika):
yes
y^2=9^2+(3sqrt7)^2
OpenStudy (highschoolmom2010):
or am i supposed to use the whole triangle
OpenStudy (rsadhvika):
for using whole triangle, you dont know the other leg. So you cant use the whole triangle
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OpenStudy (highschoolmom2010):
ok so i was right the first time
y^2=9^2+(3sqrt7)^2
y^2=81+63
y^2=144
\[\sqrt{y^2}=\sqrt{144}\]
y=12
OpenStudy (rsadhvika):
yes !
OpenStudy (highschoolmom2010):
i think i got it now :DDDD
OpenStudy (rsadhvika):
good :) more you do more confident you wil feel gotta run, cya