Question

What is the radius of a circle in which a 30° arc is 2(pi) inches long?

@jh3power would i just multiply 2*pi then work it out like before?

Answer 1

yeah

Answer 2

well, but it should be 2pi=30/360 2pi r

Answer 3

r=radius(answer)

Answer 4

r being the radius. i would just multiply 2*pi divide 30/360

Answer 5

so r would be 12

Answer 6

if it matches the equation i just wrote above, you're right.

Answer 7

this confuses me way to much

Answer 8

so...theta/360 times 2 pi r = arc

Answer 9

r=arc times 360/theta time 1/2pi

Answer 10

well 2pi is 6.28, and 30/360 is like .0833. multiply those two i get .5

Answer 11

The length of an arc, s, is:
\(s = \dfrac{\theta}{360^o} 2\pi r\)
where \(\theta\) = degree measure of arc.

Here, \(\theta = 30\) and \(s = 2 \pi \), so

\(2 \pi = \dfrac{30^o}{360^o} 2\pi r\)

\(1 = \dfrac{1}{12} r\)

\(r = 12 \)

Answer 12

you should use my r=~ equation.

Answer 13

do you get it now?

Answer 14

don't be confused with r and arc..

Answer 15

how do you get 1, when 2pi is 6.28? and yeah i do thanks guys

Answer 16

again, look at my equation. 2pi times 1/2pi times 360/30

Answer 17

equals r

Answer 18

because arc=2pi

Answer 19

is that .5pi times 360/30?

Answer 20

no... 2pi times 1/2pi =1 !!

Answer 21

and it makes r=360/30

Answer 22

and to remind you...don't substitute for pi until you get the whole equation. it only makes it more confusing.

Answer 23

okay. i get it now,

Answer 24

welcome