Question

y=(x-3)^2+4 identify the minimum or maximum y value please help

Answer 1

the smallest \((x-3)^2\) can be is zero, because it is a square

Answer 2

so what is the smallest \((x-3)^2+4\) can be?

Answer 3

minimum value is 2. (I think so)

Answer 4

first you need to find y'
y'=2(x-3)
then 2(x-3)=0 so x=3
then find y'', y''=2 >0 for all x values
so it is the minimum value