Question

Solve algebraically: e^4x-1=24

Answer 1

\[e^{4x}-1=24\\or~e^{4x-1}=24\\or~(e^4)x-1=24\]

Answer 2

which one?

Answer 3

\[e ^{4x-1}=24 \\ e ^{4x-1}=e ^{24} \\ 4x =1 + e ^{24} \\ x=\frac{ 1+ e ^{24} }{ 4 } \]

Answer 4

the second one

Answer 5

ok, take luis solution. @Luis_Rivera thanks a lot

Answer 6

nope, he's wrong.

Answer 7

4x -1 =ln24
4x = ln24-1
\[x = \frac{ln 24 -1}{4}\]

Answer 8

I think I get it now Loser66... I have the answer key for this problem, I just didn't know how to go about getting the answer. The answer key states x=1+In24/4

Answer 9

so take my step, it's your answer, right? and step to get is there. need explanation?

Answer 10

No I got it now, I understand it better :) Thanks, you were a great help

Answer 11

yw