Question

x^2+10=3x-3 . Use the value of discriminant to determine the number and type of roots

Answer 1

Do you know what the discriminant is?

Answer 2

x^2-3x+13 = 0
discriminant = sqrt(b^2-4ac) = sqrt(9-4*1*13) = sqrt(-43)
this is complex with imaginary part

so two complex solutions

Answer 3

thanks

Answer 4

First arrange the equation in itz standard form i.e.\[x^{2}+10-3x+3=0=>x^{2}-3x+13=0\]
nw waht is discriminant?The discriminant in a quadratic equation is found by the following formula and the discriminant provides critical information regarding the nature of the roots/solutions of any quadratic equation.
discriminant= b² − 4ac
here a=1
b=-3
c=13
If \[b^{2} − 4ac > 0\]then the equation has two real roots

\[b² − 4ac = 0\] then the equation has 1 real root

b² − 4ac < 0 then the equation has two complex roots
here \[b^{2}-4ac=-43<0\]
this means this equation has two complex roots

Answer 5

@nayyy

Answer 6

yes @nayyy discriminant is -43 not sqrt(-43) I was just trying to show you why the -43 causes imaginary roots