Two fair dice are rolled. What is the probability of rolling a 2, 4 times in a row?
@jim_thompson5910 @radar @Nurali @.Sam. @e.mccormick
@dumbcow
snake eyes ... 4X in row highly improbable :)
When they say 4 times in a row, I believe what they're asking is what is the probability of rollings two 2s 4 times in a row? Or would it be what is the probabiliy of rolling two 2s twice since that is also 4.
no they mean you roll dice 4 consecutive times and each time you get a "2"
So you roll the 2 fair dice, and what is the probability of getting 2s 4 times in a row? I still am not sure of what that means.
independent events let you multiply probabilities, so all you need is probability of rolling a "2" ... then take that to 4th power
that's just (1/6)^4. So basically what they're saying is you're rolling a 2, then a 2, then a 2, and again a 2?
yes however we dealing with two dice not one (1/6)^4 is correct is you just are rolling 1 die since there are only 6 outcomes
how many outcomes result from rolling two dice?
Wait, is this question asking the chances of rolling two 1s or just getting at least one of the dice show 2?
OH ok so (1/36)^4 @dumbcow
?
correct :)
@Kainui , its rolling two "1's"
@dumbcow But 1/36 is the probability of each of the outcomes from the 36 possible outcomes we can get from the 2 dice. But I don't see why we have to take it to the power of 4. Oh wait, @dumbcow is '2' referring to the sum instead of actually rolling the '2'?
2 is sum we take it to power of 4 because each roll there is 1/36 chance of getting 2...roll 4 times
OMGGGGGGGGGGGG lol ok now that's easy. I kept thinking we are rolling a 2 and what didn't make sense to me is how can you roll a 2 when you get 2 dice. Now that I know it's sum, it's simple lol. Well ty @dumbcow for clearing that up....I misunderstood what the question was asking.
oh haha ...your welcome
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