Question

Find the value of b.

Answer 1

i have the answer but I don't know if its right

Answer 2

how the hell did we go from simple trig ratios to the law of cosines in one step??

Answer 3

ohhh I don't know... lol

Answer 4

must be the accelerated pace class
probably demoivre's theorem next
in any case you need a calculator set in degree mode and use the law of cosines to compute
\[b^2+a^2+c^2-2ac\cos(\theta)\]

Answer 5

yeah I got 4.8

Answer 6

typo there, sorry
it is \\[b^2=a^2+c^2-2ac\cos(\theta)\]

Answer 7

well 4.8157

Answer 8

i didn't do it let me try

Answer 9

\[b^2=a^2+c^2-2ac\cos(B)\]

Answer 10

okay :) cos is 37.

Answer 11

granted, B is the only theta given but ....

Answer 12

yes not one but two typos
go ahead and rub it in

Answer 13

i too get \(4.8158\)

Answer 14

haha yay so I did it right? (:

Answer 15

apparently yes
still a long way from "opposite over hypotenuse" isn't it?

Answer 16

yeah I guess haha thanks so muchhhhh.