Determine the rate law, including the values of the orders and rate law constant, for the following reaction using the experimental data provided. A + B yields products Trial [A] [B] Rate 1 0.15 M 0.12 M 1.3 × 10-2 M/min 2 0.30 M 0.12 M 2.6 × 10-2 M/min 3 0.15 M 0.24 M 5.2 × 10-2 M/min
All of the following are true for a catalyst except that it provides an alternative pathway for a reaction. increases the rate of a chemical reaction. provides a lower required activation energy. is consumed during a chemical reaction.
Your 2nd question..3 Of above seems to be correct about catalyst..Last one is false..
Determine the rate law, including the values of the orders and rate law constant, for the following reaction using the experimental data provided. A + B yields products Trial [A] [B] Rate 1 0.15 M 0.12 M 1.3 × 10-2 M/min 2 0.30 M 0.12 M 2.6 × 10-2 M/min 3 0.15 M 0.24 M 5.2 × 10-2 M/min to determine the exponents in the rate law (m,j), \[rate=k[A]^m[B]^j\] you need to examine 2 situations (trials) where one of the species was held constant. For example, in trial 1 and 2: [A] = 0.15M to [A]= 0.30 M, so we conclude [A] was doubled. [B] = 0.12 M for both so it was held constant in this situation we can ignore the effect of B on the rate and thus the rate law expression simplifies to: \[rate=[A]^m\] now look at the rate, in the same situation (trial 1 and 2). The rate doubled. Trial 1: rate=1=1^m Trial 2: rate=2=2^m m=1 Since the rate doubled we can conclude that the exponent should be 1. (If the rate had quadrupled, the exponent would be 2.) Now, do the same for [B].
@superhelp101
lolz a year ago! haha i don't get this :/
O_o
do you?
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