Question

A ball is thrown horizontally from a 17m -high building with a speed of 7.0m/s . How far from the base of the building does the ball hit the ground? how do i approach this...?

Answer 1

the initial vertical velocity of the ball is zero..
let,it will take time t to hit the ground...
using this...\[h _{y}=u _{y}+1/2g t^2\]
here \(h _{y}\)=17 m
\(u _{y}\)=0
take g=10 m/sec^2
so \[t^2=17*2/10\]
the initial horizontal velocity of ball is 7 m/s and there is no acceleration in horizontal direction
the distance from the base where the ball will hit the ground is \(v _{x}\)*t
=\[7*\sqrt{34/10}\]
~13 m