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Mathematics 17 Online
OpenStudy (anonymous):

Factor completely: x2 − 4x + 9 is this prime

OpenStudy (compassionate):

Hello, I'd first like to start off by telling Satellite to leave this thread because this is mine! You want to put them in binomials by distributing the \[x^2\] term first.

OpenStudy (anonymous):

ok

OpenStudy (compassionate):

Can you demonstrate it to me, hun?

OpenStudy (anonymous):

um this is a factor

OpenStudy (anonymous):

satellite who?

OpenStudy (compassionate):

70 + 3

OpenStudy (compassionate):

\[x^2 - 4x + 9\rightarrow (x \pm ?)(x \pm ?)\] You can see I distributed the xs.

OpenStudy (anonymous):

yes

OpenStudy (compassionate):

Now, the next step is to distribute your -4x and 9. Now, what term multiplies to get 9 but adds to get -4?

OpenStudy (anonymous):

idk

OpenStudy (anonymous):

3

OpenStudy (compassionate):

There are none. Therefore?

OpenStudy (anonymous):

prime

OpenStudy (compassionate):

No, it means it's not factorable.

OpenStudy (anonymous):

biu these are the answers (x − 1)(x − 9) (x − 3)(x − 3) (x + 3)(x − 3) Prime

OpenStudy (compassionate):

biu?

OpenStudy (anonymous):

But

OpenStudy (compassionate):

Prime

OpenStudy (anonymous):

So thats it

OpenStudy (compassionate):

Yes.

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