solve the equation. check your solution. 4=sqrt(h)-6
\[4=\sqrt{h}-6\]
Do you know the first step, hun?
no, I looked at the book but I am completely lost, I cant follow their steps. I was thinking you need to add 6 to both sides first making it \[10=\sqrt{h}\] am I right?
Yes. Go on.
then you solve for sqrt to get h?
There is no sqrt of H, since it's not h^2. So you perform the opposite action of a square root.
don't understand the opposite action, think this is where I get lost
h = 100, by the way.
Want me to explain it to you?
please in English not math, lol
Alright. One second. Let me type something up to help you understand.
k
So we have the square root in the middle. How we undo that is by squaring both sides. So if we square both sides to get the x out, we also square the 10, which gives us 100. Make sense?
so squaring 10 is 3.16, and h is 100
wait that is not right is it?
ow wait, square of h = 100, and if we take 10*10 that also =100
lightbulb just went off.....squaring is opposite of square root!!!!!
\[10 = \sqrt{h}\rightarrow 10^2 = \sqrt{h^2}\] Okay, so we know that if we have 2 terms under the square root symbol we can remov ethem. \[10^2 = \sqrt{h^2} = 100 = h\]
CORRECT!
\[4=\sqrt{100}-6\]
So the same thing. 10 = sqrt{100} Now square both numbers 100 = 10,000 Which is false.
ok, I see what you are saying....got it...I am going to write these steps down for the next problems, thanks and I appreciate your patience!!!!
No problem. Remember to give me a medal !!
;)
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