A painter leans a 20-ft ladder against a building. The base of the ladder is 12 ft from the building. To the nearest foot, how high on the building does the ladder reach?

Question

johnweldon1993 · Answer

We would need an angle to work with here...

anonymous · Answer

it was no angle @johnweldon1993

johnweldon1993 · Answer

Hmm....|dw:1374200891457:dw|

Lets find the angle then....we have a side adjacent to the angle and the hypotenuse...what is the arccos of 12/20

That is 53.1301024 degrees...(lets say 53 degrees)

Now we have an angle....a hypotenuse...and we want the side opposite that angle...so

sin(53.1301024) = o / 20

Multiply both sides by 20

o = 20 * sin(53.1301024)

o = 16 feet...now lets check using the good old pythagorean theorem

a^2 + b^2 = c^2

12^2 + 16^2 = 20^2
144 + 256 = 400
400 = 400

That is correct...so it is 16 feet high

anonymous · Answer

thanx @johnweldon1993

johnweldon1993 · Answer

No problem!

anonymous · Answer

https://pwnd9373-ndscholarship-ccl.gradpoint.com/Resource/630568,72F,0,0,0,0,0/Assets/testitemimages/geometry_b/right_triangles_and_trigonometry/mc021-1.jpg

anonymous · Answer

In , LM = 11 and . Find KL. Leave your answer in simplest radical form.

anonymous · Answer

@johnweldon1993 can you help me

johnweldon1993 · Answer

I need 1 more side...all you write was that LM = 11   ...I need 1 more side...

anonymous · Answer

m<k=45

johnweldon1993 · Answer

Oh okay...well then we know that a 45 45 90 triangle has the ratio

1 : 1 : √2

So we know that 1 leg is 11.....so the other leg must be 11....and the hypotenuse KL would be 11 times √2

11√2 would be your answer

anonymous · Answer

thank you