find the area of the shown,which consists of a squareand nd a triangle.
|dw:1374201111834:dw|
im lost
Okay....how do we find the area of the square? Length x Width right? so what is that area?
54+54=108 and 69
Well actually I was just going to find the area of the square and area of the triangle...and then add them...so forget what you see with the triangle for now... just focus on |dw:1374202484620:dw|
54
Not quite....Area = Length times Width \[A = 54 \times 54\] So the area of the square is 2916 With me so far?
yes
2916 *69
Okay...now we know a square has 4 equal sides...so I can write this as |dw:1374202621402:dw| Do you agree?
69
How do you find the area of a triangle?
im lost
Just try not to jump ahead....it's easy once you see it...you just find the separate areas of each shape...and add them together.... We find the area of a square....the area of a square is Length times Width....correct?
yes
Okay...from your drawing... |dw:1374202863193:dw| For the square only!...The length is 54...and the width is 54.... so the area is \[Area = 54 \times 54 = 2916\] You good so far? this is the area of the SQUARE portion of our shape so far...
ok triangle 69x69=4761
Dont jump ahead.... Now....we know that a square has 4 equal sides...in our case here...each side will be 54 So I can make our picture look like |dw:1374203101662:dw| Agree?
ok
Now...to find the area of a triangle...you use the equation \[Area = \frac{ 1 }{ 2 }base\times height\] We know the BASE of the triangle...is 69 ft.....and now that I wrote the remaining sides of the square....we can see the HEIGHT of the triangle is 54ft... so this comes to \[Area = \frac{ 1 }{ 2 }69\times 54\] Can you solve that equation? *Remember this is the area of the TRIANGLE only now*
You can write it like this too \[Area = \frac{ 69 \times 54 }{ 2 }\]
1863
Correct! So now we have Area of SQUARE = 2916 Area of TRIANGLE = 1863 Now to find the area of the whole figure...just add these 2 together... 2916 + 1863 = ?
4779
Right...and that is your total area!
4779ft^2
That is correct!
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