Question

R(x)=7x+14/5-x please help! looking for asymptote

Answer 1

I found x=5 but not sure

Answer 2

5 is vertical asymptote

Answer 3

On the same equation: The horizontal asymptote is defined by the function:


x=7/5
x = -7
Rx=7/5
R(x) = -7

Answer 4

I think you are correct. Think about what happens as x gets closer and closer to 5. The numerator gets divided by a smaller and smaller number the closer x gets to 5. What happens when you take some constant and divide it by something really, /really/ small?

Answer 5

I see...yes it is the vertical (x=5) they asking for horizontal...

Answer 6

sub those values in y and find which one will not be possible

Answer 7

oh, for the horizontal I think you might have some rules in your book to guide you. Some like if n >m, or n = m, or n < m, with n and me being the degree of the polynomials in the numerator and denominator.

Answer 8

if you do you would find that R(x) = -7 is impossible

Answer 9

since the degree (of one) is the same in the top and bottom of your fraction, you have a case of n = m. If I remember, that is just the ration of the coeffiecients, 7/(-1).

Answer 10

I would have answered that h.a. is y = -7 also. So if that is incorrect I guess I would have got it wrong.

Answer 11

Ok thank you very much! so should i answer This has no solution, so the denominator is never zero. Then the domain is "all x".?

Answer 12

so you want to find the domain of this?

Answer 13

yes,correct

Answer 14

well, domain is x all real except 5

Answer 15

if x = 5 is a v.a. then you have to exclude it from your domain. Unless you figured out how to divide by zero.

Answer 16

as x cannot be 5
since denominator cannot be 0

Answer 17

ok

Answer 18

I think you've got everything you need: h.a. is y = -7, v.a. is x = 5. Domain is {x| x is not equal to 5} or maybe like this, (-infinity, 5) U (5, infinity).

Answer 19

i dont think she wants to sketch this lol

Answer 20

lol. personally, I would have just put it in my graphing calculator unless I needed to show the work.

Answer 21

i did sketch it!! :)

Answer 22

i do have to show my work, and my graph is a T85...old and i don't get how to use it. but thank you for the help

Answer 23

http://www.wolframalpha.com/input/?i=y%3D%287x%2B14%29%2F+%285-x+%29

Answer 24

check if you got your sketch right :P

Answer 25

this is a great link, thanks!

Answer 26

btw that website can solve any algebra question or calculus question with working out...
Sadly if you want working out its not free

Answer 27

well it does help..