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Mathematics 8 Online
OpenStudy (anonymous):

1. Graph the function f(x) = –x3 + 1 by hand (not to be submitted). Part 1: Use complete sentences to explain the process of graphing f(x) = –x3 + 1. Part 2: What is the end behavior of f(x) = –x3 + 1? 2. The binomial x + 2 is the divisor of 4x3 – 9x2 – 30x + 8. Use complete sentences to explain how you use (either) polynomial division or synthetic division to find the quotient. Be sure to provide this quotient in your answer.

jimthompson5910 (jim_thompson5910):

how far did you get

OpenStudy (anonymous):

no where. this topic hasnt been my strong suit. i keep messing up

OpenStudy (anonymous):

so ive kinda stop trying for most

jimthompson5910 (jim_thompson5910):

to graph any function, you just need to graph a bunch of points

jimthompson5910 (jim_thompson5910):

the more points you graph, the more accurate your graph will be

jimthompson5910 (jim_thompson5910):

to get any point, you plug in a value of x to get a corresponding value of y ex: plug in x = 0 into y = -x^3 + 1 to get y = 1 ----> the point (0,1) is on the graph

jimthompson5910 (jim_thompson5910):

get enough points and you'll have the basic shape/form of the graph down

OpenStudy (anonymous):

i used an online graphing calculator for this even tho she wants it by hand but is this what it should look like?

jimthompson5910 (jim_thompson5910):

its says "(not to be submitted). ", so who cares how you get the graph really

jimthompson5910 (jim_thompson5910):

but yes that looks right

jimthompson5910 (jim_thompson5910):

so what's the end behavior?

OpenStudy (anonymous):

left side continues going up and right side continues going up y-intercept is 1

OpenStudy (anonymous):

right?

jimthompson5910 (jim_thompson5910):

left is up, but right is down (look at the graph)

OpenStudy (anonymous):

thats what i said.

jimthompson5910 (jim_thompson5910):

no you said "right side continues going up"

OpenStudy (anonymous):

oh well i meant down :/

jimthompson5910 (jim_thompson5910):

ah ok

jimthompson5910 (jim_thompson5910):

so that's the end behavior

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