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Mathematics 23 Online
OpenStudy (anonymous):

cscx- cotx / sec x -1= cot x

OpenStudy (anonymous):

can you post your question once again propoerly...

OpenStudy (anonymous):

is it (cosecx - cotx)/(ssecx-1) if so change all in terms of sinx and cos x

OpenStudy (anonymous):

cosec x - cotx = 1/sinx -cosx/sinx=(1-cosx)/sinx

OpenStudy (anonymous):

also secx -1 =1/cosx -1 =(1-cosx)/cosx

OpenStudy (anonymous):

hence (cosecx - cotx)/(ssecx-1) = (1-cosx)/sinx / (1-cosx)/cosx =cosx/sinx =cotx

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