Write the equation of the line that is perpendicular to the line 2x − 3y = 3 and passes through the point (−8, 2).

y = x − 10
y = x + 10
y = −x − 10
y = −x + 10 please help!

Question

Write the equation of the line that is perpendicular to the line 2x − 3y = 3 and passes through the point (−8, 2).
 	
	y = x − 10
	y = x + 10
	y = −x − 10
	y = −x + 10       please help!

jim_thompson5910 · Answer

2x − 3y = 3

-3y = -2x + 3

-3y/(-3) = -2x/(-3) + 3/(-3)

y = 2/3x - 3

jim_thompson5910 · Answer

The slope here is 2/3

flip the fraction and flip the sign to get -3/2

jim_thompson5910 · Answer

y = mx + b

y = (-3/2)x + b

2 = (-3/2)*(-8) + b

2 = 24/2 + b

2 = 12 + b

2 - 12 = b

-10 = b

b = -10


So the equation of the perpendicular line is y = -3/2x - 10

anonymous · Answer

To check your answer,you can simply substitute the values of x and y in both the cases and see in which case LHS=RHS and that will the answer

campbell_st · Answer

well I think you have a typo in your question ans none of the answer choices match the correct solution.

jim_thompson5910 · Answer

the fractions didn't copy/paste correctly campbell_st

anonymous · Answer

why 2nd one is a match

anonymous · Answer

2=-8+10
2=2