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Mathematics 21 Online
OpenStudy (anonymous):

Write the equation of a hyperbola with vertices at (-4, 0) and (4, 0) and co-vertices (0, 5) and (0, -5)?

OpenStudy (anonymous):

i am getting to be an expert at these !

OpenStudy (anonymous):

it is clear what the center is ?

OpenStudy (anonymous):

No, I'm not sure what the center is

OpenStudy (anonymous):

half way between the vertices

OpenStudy (anonymous):

so once again at the origin, which makes life much easier

OpenStudy (anonymous):

also before you can find the equation you need to have an idea of what it looks like then it will be really easy to find the equation

OpenStudy (anonymous):

ok, I think I understand now, I will type the answer once I finish writing it down

OpenStudy (anonymous):

since vertices are at \((-4,0)\) and \((4,0)\) the center is half way between them at \((0,0)\) and i looks like this |dw:1374247252556:dw|

OpenStudy (anonymous):

ok i will wait and see what you write

OpenStudy (anonymous):

would the answer be y^2/16-x^2/25=1?

OpenStudy (anonymous):

damn so close

OpenStudy (anonymous):

or is the x before the y?

OpenStudy (anonymous):

hint: because it looks like the ugly picture i wrote above, the \(x^2\) term should be first

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

that is why i wrote above "also before you can find the equation you need to have an idea of what it looks like"

OpenStudy (anonymous):

oh, so then it would be x^2/25-y^2/16=1

OpenStudy (anonymous):

yes lets check it http://www.wolframalpha.com/input/?i=hyperobola+x^2%2F16-y^2%2F25%3D1 yup

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