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OpenStudy (anonymous):
ok....let us split this as \[w ^{3}x ^{5}y ^{3}=w ^{3}x ^{6}y ^{5}\]
OpenStudy (anonymous):
those w^3 cancel out
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
then x^s and one x^5 from x^6 cancel out
OpenStudy (anonymous):
also y^3 and one y^3 from y^5
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OpenStudy (anonymous):
leaving behind 1=xy^2
OpenStudy (anonymous):
thats the answer..
OpenStudy (anonymous):
@Krishnadas is that how you write it in factor form
OpenStudy (anonymous):
no no no..factor form is different..for example suppose you have x^2+3x+2..okay?
OpenStudy (anonymous):
we can write it us (x+2)(x+1)
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OpenStudy (anonymous):
thats what we call factorized form of the eqn
OpenStudy (anonymous):
cause the first question i asked says to find the complete factored form of the polynomial
OpenStudy (anonymous):
okay..
OpenStudy (anonymous):
suppose you got x^2+3x+2 to factorize completely
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
you can quickly do it like as i do..
OpenStudy (anonymous):
which numbers give 2 when multiplied...and gives 3 when added.........the last term of the polynomial should be got when we multiply them and should get the middle term when added...which are they?
OpenStudy (anonymous):
you got it??
OpenStudy (anonymous):
2 and one
OpenStudy (anonymous):
so the factorized form will be (x+2((x+1)
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