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Mathematics 30 Online
OpenStudy (anonymous):

w^3 x^5 y^3-w^3 x^6 y^5 = helppp!!

OpenStudy (anonymous):

ok....let us split this as \[w ^{3}x ^{5}y ^{3}=w ^{3}x ^{6}y ^{5}\]

OpenStudy (anonymous):

those w^3 cancel out

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

then x^s and one x^5 from x^6 cancel out

OpenStudy (anonymous):

also y^3 and one y^3 from y^5

OpenStudy (anonymous):

leaving behind 1=xy^2

OpenStudy (anonymous):

thats the answer..

OpenStudy (anonymous):

@Krishnadas is that how you write it in factor form

OpenStudy (anonymous):

no no no..factor form is different..for example suppose you have x^2+3x+2..okay?

OpenStudy (anonymous):

we can write it us (x+2)(x+1)

OpenStudy (anonymous):

thats what we call factorized form of the eqn

OpenStudy (anonymous):

cause the first question i asked says to find the complete factored form of the polynomial

OpenStudy (anonymous):

okay..

OpenStudy (anonymous):

suppose you got x^2+3x+2 to factorize completely

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

you can quickly do it like as i do..

OpenStudy (anonymous):

which numbers give 2 when multiplied...and gives 3 when added.........the last term of the polynomial should be got when we multiply them and should get the middle term when added...which are they?

OpenStudy (anonymous):

you got it??

OpenStudy (anonymous):

2 and one

OpenStudy (anonymous):

so the factorized form will be (x+2((x+1)

OpenStudy (anonymous):

so can you factorize x^2+4x+3?

OpenStudy (anonymous):

give it a try:)

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