Question

√(6x+5)=√53

Answer 1

\[\sqrt{6x+5}=\sqrt{53}\]

Answer 2

First we should square both sides to get rid of the square root.

Answer 3

What do you get when we do that?

Answer 4

i dont know how to do that. im bad at radicals

Answer 5

and everything else in math

Answer 6

\[\sqrt{6x+3}=\sqrt{53}\]
squaring both sides we find
6x+3=53
6x=53-3
6x=50
x=50/6
i.e. x= 25/3

Answer 7

aw :( ok. well, when we square a square root, suchas \((\sqrt{2})^2\) we're essentially saying \((\sqrt{2} \cdot \sqrt{2})\) and multiplying two radicals, you get a whole number.

Answer 8

\[(\sqrt{a})^2 =a\]

Answer 9

now that we know that multiplying two radicals together gives you a whole number, we can treat \(\sqrt{6x+3}\) as a number under a radical,and the same with \(\sqrt{53}\). squaring these two gives you whole numbers. \[\large (\sqrt{6x+3})(\sqrt{6x+3}) = (\sqrt{53})(\sqrt{53})\]\[\large 6x+3 = 53\] And nowwe'll solve for our x value by moving our constants over to one side and keeping our variable and anything attached to it on the other side. \[\large 6x = 53-3\]\[\large 6x = 50\]

Answer 10

thank you!