Question

The function f(x) = the square root of x is unbounded as x approaches infinty. However, your friend claims that f is in fact bounded by the constant 10 (i.e., (fx) < or equal to 10 for any x) to refute this claim, you can:
a. point out that f(x) is undefined for negative values of x
b. point out that f(122) = the square root of 121 = 11 > 10
c. graph f(x) over the interval [0,100)
d. compute f(x) for all values x < or equal to 100
e. graph f(x) over the interval [0,10)

Answer 1

this is ezzzyyyy

Answer 2

Then can I please get the answer then? lol

Answer 3

C won't work. The value of the function at x=100 is ten.

Answer 4

Option b gives you a proof by counterexample. The friend claims it never gets bigger than ten; by plugging in 121, we get eleven, a contradiction that shows the upper bound at ten is not correct.