Question

Solve the following system of equations for x:
5x + 6 = 4x + y + 16
3(x - 2) – y = 2x - 3y + 5

Just to check. When I did this, I got x = 13

Answer 1

The following is not your normal class room solution.
Eliminate is a Mathematica function that in the case of the expression below will eliminate y.

Eliminate[ {6+5 x=16+4 x+y,3 (-2+x)-y=5+2 x-3 y}, y ]
3x = 31\[x=\frac{31}{3} \]

Answer 2

\[\left\{x=\frac{31}{3},y=\frac{1}{3}\right\} \] is the solution to the equations.

Answer 3

I don't really understand how you got those answers.

Answer 4

Class room method:
Solve the first equation for y and simplify.
y = x - 10
Now replace each y in the second equation with (x-10) and simplify.

Answer 5

Ohh. Okay, that makes sense.

Answer 6

{10 + 3 (-2 + x) - x = 5 - 3 (-10 + x) + 2 x}\[4+2 x=35-x\]3x = 31
x = 31/3

Answer 7

Thank you for the medal.