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Mathematics 17 Online
OpenStudy (anonymous):

Adam kicks the football in his backyard. The path of the football when kicked can be represented by the quadratic function y = - 16x^2 + 85x where x is the horizontal distance (in feet) and y is the height (in feet). How far does Adam kick the football? Express your answer as a decimal rounded to the nearest hundredth.

OpenStudy (campbell_st):

well to find the horizontal distance travelled by the ball, let y = 0.., so the ball is on the ground, so \[0 = x(-16x + 85)\] so I'll do the easy solution x = 0 you can find the other by solving -16x + 85 = 0

OpenStudy (campbell_st):

if you need the vertical height, because the path of the ball is a parabola, just find the line of symmetry x = -b/2a so x = -85/32 substitute the x value to find the max height.

OpenStudy (campbell_st):

oops should be x = -85/-32

OpenStudy (anonymous):

2.65625 ?

OpenStudy (campbell_st):

well start with the horizontal distance x = 5.3125..... so the ball travels 5.3125 ft

OpenStudy (campbell_st):

its interesting in that the ball gets to a highest point of 112.89 feet

OpenStudy (anonymous):

is that rounded ?

OpenStudy (campbell_st):

well hundredths is 2 decimal places... so round 5.3125 to 2 decimal places

OpenStudy (anonymous):

so is it 5.31

OpenStudy (campbell_st):

yep... thats the horizontal distance travelled.

OpenStudy (anonymous):

Its wrong

OpenStudy (anonymous):

it said this when i got it wrong ? Use your graphing calculator to find the solution.

OpenStudy (campbell_st):

so what distance are you being asked for... the horizontal distance or the vertical height.

OpenStudy (campbell_st):

do you have a graphing calculator..?

OpenStudy (anonymous):

Horizontal Im guessing. It says nothing about vertical. and yes i do .

OpenStudy (campbell_st):

here is a copy of the graph of your curve. hope this helps

OpenStudy (campbell_st):

so I'd press the y = key and type in the equation... and then find the zeros.

OpenStudy (anonymous):

I typed it in y= what do after ?

OpenStudy (campbell_st):

press enter and you should get the curve on your screen

OpenStudy (anonymous):

i dont i get a line going down

OpenStudy (campbell_st):

you may need to press the window key, and resize y max = 120 y scl 10 and x max = 6

OpenStudy (anonymous):

ok i did

OpenStudy (anonymous):

what do i do after

OpenStudy (campbell_st):

next you have a trace key...? and above it in yellow you have CALC

OpenStudy (anonymous):

correct

OpenStudy (campbell_st):

press the 2nd key and then CALC you get a list of options... select zero

OpenStudy (anonymous):

ok done

OpenStudy (campbell_st):

then using the arrow keys move the curser to a point just below the point where the curve cuts the x axis, press enter and then move the curser again to a point above the cut.. press enter... and I think you have to press enter again. It will then give a value for the zero

OpenStudy (campbell_st):

I haven't done this in ages... so it may not work

OpenStudy (anonymous):

the numbers just keep going up for x and y

OpenStudy (campbell_st):

ok... so just press 2nd and CALC again

OpenStudy (anonymous):

kk

OpenStudy (campbell_st):

and you get a menu list press the number on the keypad that matches zeros

OpenStudy (anonymous):

wait what ? so 2

OpenStudy (campbell_st):

yep you should be back with the graph and somewhere on the screen it says lower bound

OpenStudy (anonymous):

It says left not lower ..

OpenStudy (campbell_st):

ok... thats fine, type in 3 when you get right type in 8... these values should eb either side of the point where the curve cuts the x axis I think its 3 enter, then 8 enter

OpenStudy (campbell_st):

after that is it says estimate just press enter

OpenStudy (campbell_st):

you should get a number displayed on the screen for of around 5.3 its the max horizontal distance

OpenStudy (anonymous):

once i enter 3 its y=511 but once i try 8 it says Error invalid

OpenStudy (anonymous):

its not letting me type 8

OpenStudy (campbell_st):

try 6

OpenStudy (anonymous):

it says y= 766

OpenStudy (campbell_st):

ok... well I'm only guessing now at how to use your calculator.. just try putting in the vertical height 112.89. the maths in finding the horizontal distance is correct... 5.3125 ft so I don't know where to go

OpenStudy (anonymous):

ok so you dont know for sure the final answer ?

OpenStudy (campbell_st):

No, the mathematics is correct. Its just which answer do you need. If you graph the equation it cuts the x-axis at 0, 5.3125

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