Question

why wont anyone answer my question i posted

Answer 1

the quarter shows head one half of the time i.e. \(\frac{1}{2}\)

Answer 2

only one coin shows head
8 possibilties all together
h, h ,h
h, h , t
h, t, h
t, h, h
h, t, t
t, h, t
t, t, h
t, t, t

Answer 3

out of those 8 equally likely possibilities, three have only one head
so second one is \(\frac{3}{8}\)

Answer 4

For the first problem if the quarter is heads, then the nickel can be head or tails and the same for the penny so there are 4 possible events that the quarter comes up heads.

So we have

4/{total # of events} = P(Quarter is heads).

Now the problem is, "what is the total # of events?" For that, we just need to consider is the quarter comes up tails. In this case there are the same 4 events as when it came up heads, i.e. 4. So we have

4/8 = 1/2 = P (Quarter is heads). Using this as an example try solving the others

Answer 5

penny and nickel show heads
if the list i wrote above represent Q, N, P
then there are two that fit the bill
h, h, h
t, h, h

Answer 6

thank you!!!!

Answer 7

answer to the third one is therefore \[\frac{2}{8}=\frac{1}{4}\]

Answer 8

all three coins land the same side
two fit that bill
h, h, h
t, t, t
so again \(\frac{2}{8}=\frac{1}{4}\)
now it should be routine right?