Question

please help?

Answer 1

Using complete sentences, explain how to graph x + 3y = 3 using the x- and y-intercepts method.

Answer 2

To find the x-intercepts, substitute y with 0 and solve for x. To find the y-intercepts, substitute x with 0 and solve for y

Then rearrange the equation from
x+ 3y = 3
3y = -x + 3
y = (-1/3)x + 1
Graph the point (0, 1) then go down one and over to the right 3.

Answer 3

ugh!!! thank you sooo much!!! mind one more?

Answer 4

I can try

Answer 5

Using complete sentences, explain how to graph y = 1/2x - 3 using the slope-intercept method.

Answer 6

All that is, is the last part from the previous question. Slope-Intercept equation: \[y = mx + b\] You always graph the point (0, b) first. Then simply graph the slope. I'm sure you can use this knowledge to answer your question. If you still get stuck, let me know.

Answer 7

Also, whenever you have a fraction for a slope
\[\frac{ a }{ b }=\frac{ Up/Down }{ Left/Right }\]

Answer 8

hmmm still kinda confused

Answer 9

would u mind answering this one so i can us it as an example for my next one?

Answer 10

Okay, I'm going to give you an example without giving you the answer to your primary question, because this basic stuff that you'll definitely need to know for yourself in the future.

If I have \[y=(\frac{ 3 }{ 5 })x+10\] I'm first going to graph the point (0, 10). Then from that point, I'm going to go up 3 units, and over to the right 5 units.

Remember,\[\frac{ Up/Down }{Right }\]
And I also made a mistake -- if the slope is ever negative, you'll never really go left. You will always go to the right. The negative affects the numerator and determines whether it goes up or down first.

Answer 11

a mistake on this one or the first one?

Answer 12

It was a mistake on my part when I said if the denominator is negative you go left -- You'll never go left. You'll always go to the right for whatever value is in the denominator.

Answer 13

ohhh gotcha!

Answer 14

Do you understand how to solve your second problem now? :)

Answer 15

yes thank you :)

Answer 16

You're welcome :)