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@Krishnadas @Isaiah.Feynman
f(x) = 8x write it in terms of y. y = 8x Switch x and y x = 8y solve for y. y= x/8 rewrite it as f inverse. \[f^{-1}(x) = \cfrac{x}{8}\]
i thought it stays as y
it does stay as y, we switched around the x and y first and RESOLVED for y, and because we resolved for y,we found the inverse function.
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Say f(x) = 8x f(1) = 8 \(f^{-1} (x) = \cfrac{x}{8}\) \(f^{-1}(1) = \cfrac{1}{8}\)
so what does it come out to
Read my first post...
x/8
You got it.
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it says it was suppose to be y/8
well idk ugh
That answer would be wrong.
@divagirl when you find inverses you switch the x and y wherever they are. Its that simple!!!
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