Question

What is generally true about rate over the course of a reaction?
Rate decreases because there are more collisions as the reaction progresses.

Rate increases because there are more collisions as the reaction progresses.

Rate decreases because the concentration of reactants decreases.

Rate increases because the concentration of products increases.

@chmvijay

Answer 1

c?

Answer 2

no of collisions will remain the same :) but the concentration of reactant decreases as time goes :) ur right

Answer 3

yay! can you check my work on something?

Answer 4

Determine the rate law, including the values of the orders and rate law constant, for the following reaction using the experimental data provided.

X + Y yields products


Trial [X] [Y] Rate
1 0.20 M 0.15 M 2.4 × 10-2 M/min
2 0.20 M 0.30 M 4.8 × 10-2 M/min
3 0.40 M 0.30 M 19.2 × 10-2 M/min

Answer 5

trial 1 to 2 X is held constant; but Y doubles - so does the rate - thus rate is linear in Y



trial 2 to 3; Y is fixed but X doubles, but rate goes up by a factor of 8
-rate is 2^3


rate = k[X][Y]^3

plug in trial one

2.4 E-2 M/min = k* .2 moles/liter * (.15 moles/liter)^3

2.4 E-2 M/min = k * 6.75 E-4 moles^4 / l^4

k = 35.6 l^4/min*moles^3

Answer 6

doubling the Y has doubled the rate constant in fst and 2nd case

Answer 7

A->1

B->2

Answer 8

C--->4

Answer 9

what does a-1
b-2
c-4mean?

Answer 10

X factor of increase

Answer 11

ok can you show the work?

Answer 12

like same you do as u a have solved already right

Answer 13

k = 35.6 l^4/min*moles^3 is that the rate law?

Answer 14

did i answer the question correctly then? lol

Answer 15

yup :)

Answer 16

ok :)

A catalyst increases the reaction rate of a reaction by

lowering the potential energy of the reactants.

raising the potential energy of the products.

providing a lower activation energy for the reaction.

decreasing the enthalpy change of the reaction.

Answer 17

i no the definition but these answers dont make sense

Answer 18

i wanna say a

Answer 19

catalyst always decreases the activation energy required for the reaction :)

Answer 20

so c?

Answer 21

yup

Answer 22

For the following reaction, it is found that doubling the amount of A causes the reaction rate to quadruple while doubling the amount of B causes the reaction rate to double. What is the best rate law equation for this reaction?

A + B yields 2C

Answer 23

rate = k[A]2[B]

rate = k[A][B]

rate = k[A][B]2

rate = k[A]1/2[B]

Answer 24

LOL still how many u have

Answer 25

last one

Answer 26

c?

Answer 27

why its C

Answer 28

?

Answer 29

got any idea