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Mathematics 13 Online
OpenStudy (anonymous):

What is the relative maximum value for the function: 7/x^2+5?

OpenStudy (harsimran_hs4):

can you rewrite the expression(using equation generator or proper brackets) ?

OpenStudy (ybarrap):

Is this the problem? \[7/x^2+5 \]

OpenStudy (anonymous):

7/(x^2+5)

OpenStudy (harsimran_hs4):

so 7 is constant you just need to maximize (1/(x^2+5)) or minimize (x^2 + 5) so what is the minimum value of (x^2 + 5) ?

OpenStudy (anonymous):

That's what I don't understand how to do

OpenStudy (harsimran_hs4):

consider our problem minimize (x^2 + 5) since 5 is a constant so we just need to minimize x^2, x^2 is always greater than or equal to 0. so the x^2 `s minimum value is 0 x^2 + 5 `s is 5 so 7/5 should be the final answer clear ?

OpenStudy (anonymous):

Somewhat. What exactly does it mean when it asks for the relative maximum instead of absolute maximum?

OpenStudy (harsimran_hs4):

Relative maximum is a maxima which is determined locally (say about a point)|dw:1374342841668:dw|

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