Solutions for y= -3/2x + 4
Factor the bottom and you'll get \[\frac{ -3 }{ 2(x+2) }\]. From there you can see what the solution is
I'm sorry but that doesn't make sense to me...
Okay are you confused by the factoring? Or are you not sure what the solution is?
well I found what the y-intercept is.. obviously its 4. But I need other points for it so I could graph it
Alright well now with the factoring you can see there'll be a Vertical Asymptote at -2. This is because -2 makes the bottom 0, which makes the function 3/0. That is undefined. The HA is simply 0. So now you'll have all the information to graph your function.
Vertical Asymptote?
Yep, do you know what asymptotes are?
no..
Asymptotes are where the function does not exist. So in this case it can never be -2. So what you do is have an invisible barrier at -2 and draw the function like this: http://www4b.wolframalpha.com/Calculate/MSP/MSP71741g8e9edb679bd73700004g53f9d63ec48f5b?MSPStoreType=image/gif&s=57&w=299.&h=110.&cdf=RangeControl
\[y= -3/(2x) + 4\] \[y= (-3+4(2x))/(2x)\] \[y=(-3 + 8x)/(2x)\] x can not equal 0, so 0 is the asymptote. Solution can be all x where \[x \neq0\]
@ybarrap I think you are misinterpreting the questions. He meant to write it as (-3)/(2x+4)
In that case, your solution is correct.
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