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Mathematics 20 Online
OpenStudy (anonymous):

Solutions for y= -3/2x + 4

OpenStudy (anonymous):

Factor the bottom and you'll get \[\frac{ -3 }{ 2(x+2) }\]. From there you can see what the solution is

OpenStudy (anonymous):

I'm sorry but that doesn't make sense to me...

OpenStudy (anonymous):

Okay are you confused by the factoring? Or are you not sure what the solution is?

OpenStudy (anonymous):

well I found what the y-intercept is.. obviously its 4. But I need other points for it so I could graph it

OpenStudy (anonymous):

Alright well now with the factoring you can see there'll be a Vertical Asymptote at -2. This is because -2 makes the bottom 0, which makes the function 3/0. That is undefined. The HA is simply 0. So now you'll have all the information to graph your function.

OpenStudy (anonymous):

Vertical Asymptote?

OpenStudy (anonymous):

Yep, do you know what asymptotes are?

OpenStudy (anonymous):

no..

OpenStudy (anonymous):

Asymptotes are where the function does not exist. So in this case it can never be -2. So what you do is have an invisible barrier at -2 and draw the function like this: http://www4b.wolframalpha.com/Calculate/MSP/MSP71741g8e9edb679bd73700004g53f9d63ec48f5b?MSPStoreType=image/gif&s=57&w=299.&h=110.&cdf=RangeControl

OpenStudy (ybarrap):

\[y= -3/(2x) + 4\] \[y= (-3+4(2x))/(2x)\] \[y=(-3 + 8x)/(2x)\] x can not equal 0, so 0 is the asymptote. Solution can be all x where \[x \neq0\]

OpenStudy (anonymous):

@ybarrap I think you are misinterpreting the questions. He meant to write it as (-3)/(2x+4)

OpenStudy (ybarrap):

In that case, your solution is correct.

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