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Use Euler's formula to write the given expression e^2-(pi/2)i in the form a+ib.
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is it \[\huge e^{2-\frac{\pi}{2}i}\]
Yes.
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strange question indeed, but if its that, then i'll do \(\dfrac{e^2}{e^{i \pi/2}}\) and find e^(i pi/2) first
do u know how to get e^(i pi/2) ??
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use same formula as i gave in last question, \(e^{i \theta}=\cos \theta+i\sin \theta\)
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So I got e^2/i, now what?
Because e^i*pi/2=i.
that could be the answer but the denominator is not real, to rationalize the denominator, you can multiply and divide by 'i' and use the fact that i^2=-1 in the denominator
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I forgot to say thank you.
no problem :) i'll forget to say welcome :P
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