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Mathematics 20 Online
OpenStudy (anonymous):

simplify | (7-sqrt(2)) (8+sqrt(2))

OpenStudy (anonymous):

\[(7-\sqrt{2})(8+\sqrt{2})\] This question should be answered using FOIL. First -> Outside -> Inside -> Last

OpenStudy (anonymous):

How do I do that?

OpenStudy (anonymous):

7 and 8 are the First terms. \[-\sqrt2 and + \sqrt2 \] are the Last terms. Inside are the two terms in the middle Outside are the two terms on either end. Does that make sense?

OpenStudy (anonymous):

Multiply the first terms together, then the Inside terms, then the outside terms, then the last terms. Add them all together (using appropriate signs) and combine like terms.

OpenStudy (anonymous):

so would it end being 56sqrt2 ?

OpenStudy (anonymous):

No. Can you show me your work, one step at a time?

OpenStudy (anonymous):

First \[7 * 8 = 56\] Inside: \[8 * -\sqrt2 = -8\sqrt2\] Outside: \[7 * \sqrt2 = 7\sqrt2\] Last: \[-\sqrt2 * \sqrt2 = -\sqrt4 = -2\]

OpenStudy (anonymous):

Do you understand where each of these equations come from?

OpenStudy (anonymous):

Kind of

OpenStudy (anonymous):

First: The product of the first terms in each group.

OpenStudy (anonymous):

Outside: The product of the terms farthest from the center.

OpenStudy (anonymous):

Inside: The product of the terms closest to the center.

OpenStudy (anonymous):

Last: The product of the last terms in each group.

OpenStudy (anonymous):

Make more sense now?

OpenStudy (anonymous):

Yes actually

OpenStudy (anonymous):

Great! So, know you add all of the terms together. Don't try to combine like terms just yet. Write out your equation. Use the Equation button under the reply box to write a properly formatted equation. (It's easier to read)

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