Question

please help I need to graph the equation using the x and y intercepts x/7-y/5=1

Answer 1

Do you know what a y-intercept is?

Answer 2

0

Answer 3

It is a point that solves the equation where x = 0.
The x-intercept is the opposite.

Answer 4

now i'm comfused

Answer 5

To find the y-intercept, plug 0 in for x and solve for y. You will come up with a point that is (0,y)

Answer 6

The intercept on a certain axis is a point where the graph crosses it, two intercepts define the graph of a linear equation. So the value on the other axis is = 0; for y-int, x=0 and for x-int, y=0
First task is to get the equation in intercept form, meaning that the variables should be on different sides of the equation to get to the form: y = mx + b
When x = 0, b represents the y-int.
Now, getting the equation in the desired form:
\[\frac{ x }{ 7 }-\frac{ y }{ 5 }=1\] Subtract x/7:
\[-\frac{ y }{ 5 }=1-\frac{ x }{ 7 }\]Multiply by (-5):
\[y=\frac{ 5x }{ 7 } - 5\] So, for the y-int, x=0, then:
\[y=\frac{ 5*0 }{ 7 } - 5= \frac{ 0 }{ 7 } -5=-5\] Y-int is defined (0,-5) For X-int y=0:
\[0=\frac{ 5x }{ 7 } - 5\] Add 5 to both sides:
\[\frac{ 5x }{ 7 } =5\] Multiply by 7:
\[5x=35\]Divide by 5:
\[x =7\] Now, X-int is also defined (7, 0), now place the 2 points which define the line graph and connect them, you're done!

And, that's it sort of, the drawing is sluggish, but you should get it, cheers