Question

For the following true conditional statement, write the converse. If the converse is also true, combine the statements as a biconditional.

If x = 9, then x2 = 81.

a)If x2 = 81, then x = 9.
b)If x2 = 81, then x = 9.
x2 = 81 if and only if x = 9.
c)If x2 = 9, then x = 81.
d)If x2 = 81, then x = 9.
x = 9 if and only if x2 = 81

Answer 1

If x = 9, then x2 = 81.

p: x = 9
q: x^2 = 81

The given conditional is p-->q

The converse of p-->q is the following: q-->p


So, the converse is:

If x^2 = 81, then x = 9.

@elizabethvilleda --> Is the converse true?

Answer 2

yes??

Answer 3

What number times itself will give 81 as a product? Post what you think and we'll compare answers. Okay?

Answer 4

9*9

Answer 5

Yes.
Question: Is there another number that you can multiply times itself and also get 81? [Hint: think negative.]

Answer 6

ummm not that i know off

Answer 7

What does (-9) times (-9) equal?

Answer 8

ohh 81 lol

Answer 9

Now, we have to determine if the converse is true.

The converse is: If x^2 = 81, then x = 9.
which means if you square a number and get 81, then the number you squared HAS to be 9.

Because you squared (-9) and got 81, the converse is false.

The instructions state that we are to write the biconditional if the converse is true. The converse is false, so that's it for this problem.

Questions?

Answer 10

ok i got it thanks sooo much
!!

Answer 11

You're welcome.