What is the mass, in grams, of a sample of 6.12 × 1024 atoms of manganese (Mn)? Show your work or explain the steps that you used to determine your answer.

Question

aaronq · Answer

divide the number of given atoms by avogadros number to find the number of moles (n).

moles=# of atoms/avogadros number

then use the periodic table to find the molar mass of manganese

since, moles=mass/molar mass

multiply the amount of moles by Mn's molar mass to find the amount of grams in the sample.

anonymous · Answer

(6.12 x 10^24 atoms) / (06.02 x 10^23 moles/atoms) = 10.2 Mol Mn.  Since you are finding mass you want to cancel out mass. Find molar mass so, 10.2 mol x grams/mol = your answer.

aaronq · Answer

"(6.12 x 10^24 atoms) / (06.02 x 10^23 moles/atoms)"

minor mistake with your units, it should be "...6.02 x 10^23 atoms/mole", since you're trying to cancel atoms out. They way you wrote it you would end up with "atoms^2/mol".