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Mathematics 23 Online
OpenStudy (anonymous):

Choose the equation of the line passing through the point (2, 6) and parallel to y = -3x - 4. y = 3x - 12 y = -3x y = -3x + 12 y = 3x Algebra 1 problem I'm stuck on

OpenStudy (whpalmer4):

To work such a problem, put the original line in slope-intercept form (\(y = mx + b\)) if not already there. Then you can read out the slope \(m\). Parallel lines will have identical slope. Next, take the known point \((x_0,y_0)\) and use it in the point-slope formula for a line with slope \(m\) passing through the point \((x_0,y_0)\) to write the equation for the new line. Point-slope formula is\[y-y_0=m(x-x_0)\] Then do any rearrangement necessary to get it in the form desired by the problem, and you're done.

OpenStudy (whpalmer4):

In this case, you can take a shortcut — just look for equations with the same slope, and see if they are true if you plug in the point (2,6). I would recommend you go through the motions of actually finding the equation, however; do this until it is second nature before you start "gaming" the problems.

OpenStudy (anonymous):

I got the answer thanks alot!!

OpenStudy (whpalmer4):

Great!

OpenStudy (whpalmer4):

Not so hard once you know what to do...

OpenStudy (anonymous):

Excuse me but does the same apply for perpendicular?

OpenStudy (whpalmer4):

yes, except with perpendicular lines, the product of the slopes = -1 there's one exception: if one line is horizontal or vertical, that doesn't apply, because a vertical line has an undefined slope. you have to just recognize that case from the fact that one line looks like \(x=<constant>\) or \(y = <constant>\)

OpenStudy (anonymous):

Okay, Thank you.

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