Choose the equation of the line passing through the point (2, 6) and parallel to y = -3x - 4. y = 3x - 12 y = -3x y = -3x + 12 y = 3x Algebra 1 problem I'm stuck on
To work such a problem, put the original line in slope-intercept form (\(y = mx + b\)) if not already there. Then you can read out the slope \(m\). Parallel lines will have identical slope. Next, take the known point \((x_0,y_0)\) and use it in the point-slope formula for a line with slope \(m\) passing through the point \((x_0,y_0)\) to write the equation for the new line. Point-slope formula is\[y-y_0=m(x-x_0)\] Then do any rearrangement necessary to get it in the form desired by the problem, and you're done.
In this case, you can take a shortcut — just look for equations with the same slope, and see if they are true if you plug in the point (2,6). I would recommend you go through the motions of actually finding the equation, however; do this until it is second nature before you start "gaming" the problems.
I got the answer thanks alot!!
Great!
Not so hard once you know what to do...
Excuse me but does the same apply for perpendicular?
yes, except with perpendicular lines, the product of the slopes = -1 there's one exception: if one line is horizontal or vertical, that doesn't apply, because a vertical line has an undefined slope. you have to just recognize that case from the fact that one line looks like \(x=<constant>\) or \(y = <constant>\)
Okay, Thank you.
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