Question

:EXPONENTIAL FUNCTIONS:
Provide the solution to the equation 25 = square root of 5 (2x + 6)

Answer 1

\[25=\sqrt{5} ^{2x+6}\]

Answer 2

\[25=\sqrt{5}^4\] is a start

Answer 3

alright so \[5^{2} = 5^{x +3}\]

Answer 4

then if
\[\sqrt{5}^4=\sqrt{5}^{2x+6}\] you know
\[4=2x+6\] and you can solve for \(x\)

Answer 5

@mebs okay so I get that then ?

Answer 6

well than its just a matter of exponents because the base is the same...

2 = x + 3 can you do it

Answer 7

just making sure you took out the 2 from 2x+6 and then made the other side 5^2 by ?

Answer 8

Satellite also has the correct answer as well... yes that is correct

Answer 9

Here is what my though process was.... 25 = 5^2 that's simple right....

squareroot5 = 5^(1/2)

multiply 1/2 by (2x +6) distribute the 1/2 so you get x +3 alright...

Now its the same base 5^2 = 5^x+3

Answer 10

THANKS!

Answer 11

yw =))