Question

Limits question

Answer 1

\[\Huge y=x(\sqrt[x]{3}-1)\]

Answer 2

x>infinity

Answer 3

did u try taking log on both sides ?
L = ....
log L = log (....)

Answer 4

umm not yet

Answer 5

or can you use L'Hopital's rule ?
(for that first put x=1/y)

Answer 6

we can use L hospital if we write it like..
\[\Huge y=\frac{(\sqrt[x]{3}-1)}{\frac{1}{x}}\] ?
that is what I thought..

Answer 7

yeah, but simpler way is to first put x =1/y
the derivative becomes so much simple...

Answer 8

if we take log on both sides,I tried that but log(infinity)..still undefined

Answer 9

i didn't try that because i found this way much easier...you ty this

Answer 10

why are we substituting x=1/y? didn't quite get that

Answer 11

to make it easier to use L'Hopital's rule.

Answer 12

it isn't required, but it makes derivative simple

Answer 13

any other method?

Answer 14

without L'hopitals ?
after you plug in x=1/y
there's a standard relation you can use.

or without x=1/y ?

Answer 15

\[\LARGE \frac{1}{y}(3^y-1)\]

Answer 16

\[\LARGE \frac{3^y-1}{y}\],oh

Answer 17

is it log a?