80=10〖log〗_10*x/〖10〗^(-12)

How do I find x? Do I simply times by x then divide by 80?

Question

80=10〖log〗_10*x/〖10〗^(-12)

How do I find x? Do I simply times by x then divide by 80?

anonymous · Answer

It just means, 10log_10, I've been taught to type it out like that.

anonymous · Answer

so  〖log〗= log

loser66 · Answer

ha, TJ here, you are safe. wait for him

terenzreignz · Answer

That's not fair, what if I only came to watch? :3

Oh well, anyway.... ^_^

terenzreignz · Answer

We need to remove all ambiguities, is THIS your equation?
$$\Large80 = \frac{10\log_{10}x}{10^{-12}}$$

anonymous · Answer

10^-12 is over x and x is not apart of the log. 
Sorry for the misunderstanding and my poor explanation skills

terenzreignz · Answer

No worries :)
Mathematics is a universal language, but somehow, translations get messy... We have to establish what your equation is first...
$$\Large80 = \frac{10\log10}{\frac{10^{-12}}x`}$$

terenzreignz · Answer

This?

anonymous · Answer

Haha, sorry no no. it's 10log_10 * x/10^-12

terenzreignz · Answer

If all else fails, you could just use the draw option down there

terenzreignz · Answer

oh, I see...
$$\Large \Large80 = \frac{[10\log10]\cdot x}{10^{-12}}$$

terenzreignz · Answer

That it?

anonymous · Answer

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