Please help me with this question: (x^2+5x+4)/(x+4) - (x^2-5x+6)/(x-2) the answer is 4 but I dont know how
the first quadratic has a factorization that includes (x+4), that leaves the other factor, similar with the other term, your answer should be 4.
can you show me a step by step method?
Factor x^2 + 5x +4 What two numbers multiply to give you 4 and add to give you 5?
ab=4 and a+b=5, can you guess?
The possibilities for ab=4 are 1*4, 2*2 and lots of other non integers, but let's just stick with integers
Which of the two pairs would work to give a+b=5?
41
4 and 1
ok, those are your factors for the 1st term, because (x^2+5x+4) = (x+4)(x+1) = x^2 + 4x + 1x + (4*1) = x^2 + x(4+1) + 4*1 = x^2 + 4(a +b) + a*b, this is where the a and b come into the picture.
Do you see here why we needed ab=4 and a+b=5?
yeah
For x^2-5x+6, what a and b factors multiply to give 6 but add to give -5?
but how does the entire thing equal 4 especially when we need the common denominators? 1 and 6 -6 +1
so the factors are (x-6)(x+1), multiply out to ensure they produce the correct result
Factors should have been -2 and -3, actually
Now you have your factors. Replace the quadratics in the numerator with these factors.
(You will see 4 pop out when you simplify everything)
Thank you so much. Can you help me with the other question too? i did the same things u told me but didnt get the answer
sure
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