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Mathematics 18 Online
OpenStudy (anonymous):

Please help me with this question: (x^2+5x+4)/(x+4) - (x^2-5x+6)/(x-2) the answer is 4 but I dont know how

OpenStudy (ybarrap):

the first quadratic has a factorization that includes (x+4), that leaves the other factor, similar with the other term, your answer should be 4.

OpenStudy (anonymous):

can you show me a step by step method?

OpenStudy (ybarrap):

Factor x^2 + 5x +4 What two numbers multiply to give you 4 and add to give you 5?

OpenStudy (ybarrap):

ab=4 and a+b=5, can you guess?

OpenStudy (ybarrap):

The possibilities for ab=4 are 1*4, 2*2 and lots of other non integers, but let's just stick with integers

OpenStudy (ybarrap):

Which of the two pairs would work to give a+b=5?

OpenStudy (anonymous):

41

OpenStudy (anonymous):

4 and 1

OpenStudy (ybarrap):

ok, those are your factors for the 1st term, because (x^2+5x+4) = (x+4)(x+1) = x^2 + 4x + 1x + (4*1) = x^2 + x(4+1) + 4*1 = x^2 + 4(a +b) + a*b, this is where the a and b come into the picture.

OpenStudy (ybarrap):

Do you see here why we needed ab=4 and a+b=5?

OpenStudy (anonymous):

yeah

OpenStudy (ybarrap):

For x^2-5x+6, what a and b factors multiply to give 6 but add to give -5?

OpenStudy (anonymous):

but how does the entire thing equal 4 especially when we need the common denominators? 1 and 6 -6 +1

OpenStudy (ybarrap):

so the factors are (x-6)(x+1), multiply out to ensure they produce the correct result

OpenStudy (ybarrap):

Factors should have been -2 and -3, actually

OpenStudy (ybarrap):

Now you have your factors. Replace the quadratics in the numerator with these factors.

OpenStudy (ybarrap):

(You will see 4 pop out when you simplify everything)

OpenStudy (anonymous):

Thank you so much. Can you help me with the other question too? i did the same things u told me but didnt get the answer

OpenStudy (ybarrap):

sure

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