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Chemistry 16 Online
OpenStudy (anonymous):

A solution prepared by dissolving 4g KCL in 36.0 g H2O is said to be? A) 11.1% KCL by mass B) 0.100% KCL by mass C) 0.111% KCL by mass D) 9.00% KCL by mass

OpenStudy (anonymous):

mass %= mass of kcl/total mass*100

OpenStudy (anonymous):

what so u mean by total mass. Total mass of what?

OpenStudy (primeralph):

|dw:1374460102357:dw|

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