Question

One More Log Question

Logbase5(2x+5)=2

Answer 1

So we take 5 and raise it to the 2nd power, why is that? I just can't wrap my head around it. Maybe because i am picturing it like this

Answer 2

raise both side to be powers of 5
5^(log_5(2x+5) = 5^2
2x+5 = 25

Answer 3

you have a = b
I did
5^a = 5^b

Answer 4

\[\log_{5} 2\] This does not equal 25, am I just picturing it wrong?

Answer 5

no it does not

Answer 6

5^? = 2

Answer 7

you are not taking the log of both sides, you are raising them both to the base of the log

Answer 8

Okay so i am using a log cancellation property to get rid of the log on the left hand side?

Answer 9

x=e^1 then right?

Answer 10

yeah
lhs
5^(log_5(2x+5)) = 2x+5

Answer 11

yeah sorry :)

Answer 12

:) awesome man, so i raise it to the base to cancel out the log, then solve it like i normally would?

Answer 13

yeah