: Phosphoric Acid can be prepared by reaction of sulfuric acid with "phosphate rock" according to the following equation: Ca3(PO4)2 + 3H2SO4 - 3CaSO4 + 2H3PO4. If 131 g of Ca3(PO4)2 + and 97.2 g of H2SO4 react, which substance is limiting reactant? Answer is H2SO4. May anyone show me steps?

Question

: Phosphoric Acid can be prepared by reaction of sulfuric acid with "phosphate rock" according to the following equation: Ca3(PO4)2 + 3H2SO4 -> 3CaSO4 + 2H3PO4. If 131 g of Ca3(PO4)2 + and 97.2 g of H2SO4 react, which substance is limiting reactant? Answer is H2SO4. May anyone show me steps?

maddyx · Answer

count the number of moles of both the reactants (along with co-efficients). The one with lower number of moles (co-efficient*(given weight/molecular mass)) is the limiting reagent.