Question

the first erm of a geometric series is 3, and the sum of the first term and the second term is 15. what is the sum of the first six term?
A.1023
B.3906
C.4096
D.11718

Answer 1

i know that the second term is 12

Answer 2

the common ratio r= 2nd term / 1st term = 12/3 = ... ?

now just use the formula for sum, with a1 = 3, and n = 6
\(\large S_n=a_1\dfrac{r^n-1}{r-1}\)

Answer 3

i dont know what to plug in to what

Answer 4

you could get r= 12/3 = 4, right ?

plug in r= 4,a1 = 3 and n=6

Answer 5

\[3\frac{ 95 }{3 }\]