Question

Logarithm Help Needed, writing question below

Answer 1

@satellite73

Answer 2

nvm it's log(2) 32=5

Answer 3

You always "log-loop" when going from exponential notation to logarithmic notation.
You start with the base \((\)the \(x\) in \(x^{\large y}=z)\).
That becomes the base in the logarithm \((\)the \(x\) in \(\log_{\Large x}(z) = y)\).
Then you "loop" to the other side, 32 goes as the next number \((z\) in the logarithm\()\).
Then "loop" to the exponent. This is what the logarithm equals.